13314341132331 has 4 divisors (see below), whose sum is σ = 17752454843112. Its totient is φ = 8876227421552.

The previous prime is 13314341132329. The next prime is 13314341132333. The reversal of 13314341132331 is 13323114341331.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13314341132329) and next prime (13314341132333).

It is a cyclic number.

It is not a de Polignac number, because 13314341132331 - 2¹ = 13314341132329 is a prime.

It is a super-2 number, since 2×13314341132331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13314341132292 and 13314341132301.

It is not an unprimeable number, because it can be changed into a prime (13314341132333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2219056855386 + ... + 2219056855391.

It is an arithmetic number, because the mean of its divisors is an integer number (4438113710778).

Almost surely, 2^{13314341132331} is an apocalyptic number.

13314341132331 is a deficient number, since it is larger than the sum of its proper divisors (4438113710781).

13314341132331 is an equidigital number, since it uses as much as digits as its factorization.

13314341132331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4438113710780.

The product of its digits is 23328, while the sum is 33.

Adding to 13314341132331 its reverse (13323114341331), we get a palindrome (26637455473662).

The spelling of 13314341132331 in words is "thirteen trillion, three hundred fourteen billion, three hundred forty-one million, one hundred thirty-two thousand, three hundred thirty-one".