Base | Representation |
---|---|
bin | 11000110011001100… |
… | …11010011011100110 |
3 | 1021100220101200221211 |
4 | 30121212122123212 |
5 | 204231441331042 |
6 | 10041101502034 |
7 | 650641356415 |
oct | 143146323346 |
9 | 37326350854 |
10 | 13314402022 |
11 | 57126a6339 |
12 | 26b6b7191a |
13 | 1342572bbc |
14 | 90440b47c |
15 | 52dd58017 |
hex | 31999a6e6 |
13314402022 has 4 divisors (see below), whose sum is σ = 19971603036. Its totient is φ = 6657201010.
The previous prime is 13314401987. The next prime is 13314402041. The reversal of 13314402022 is 22020441331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13314401984 and 13314402002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3328600504 + ... + 3328600507.
It is an arithmetic number, because the mean of its divisors is an integer number (4992900759).
Almost surely, 213314402022 is an apocalyptic number.
13314402022 is a deficient number, since it is larger than the sum of its proper divisors (6657201014).
13314402022 is an equidigital number, since it uses as much as digits as its factorization.
13314402022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6657201013.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 13314402022 its reverse (22020441331), we get a palindrome (35334843353).
The spelling of 13314402022 in words is "thirteen billion, three hundred fourteen million, four hundred two thousand, twenty-two".
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