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1331455247497 is a prime number
BaseRepresentation
bin10011011000000000111…
…010101100010010001001
311201021201101221120212201
4103120000322230102021
5133303310020404442
62455355002440201
7165123462604324
oct23300072542211
94637641846781
101331455247497
1147373785a201
12196065803061
139872bb12a1b
144862ada77bb
152497a6a87b7
hex13600eac489

1331455247497 has 2 divisors, whose sum is σ = 1331455247498. Its totient is φ = 1331455247496.

The previous prime is 1331455247387. The next prime is 1331455247509. The reversal of 1331455247497 is 7947425541331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1327539491721 + 3915755776 = 1152189^2 + 62576^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331455247497 - 215 = 1331455214729 is a prime.

It is a super-3 number, since 3×13314552474973 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1331455217497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665727623748 + 665727623749.

It is an arithmetic number, because the mean of its divisors is an integer number (665727623749).

Almost surely, 21331455247497 is an apocalyptic number.

It is an amenable number.

1331455247497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331455247497 is an equidigital number, since it uses as much as digits as its factorization.

1331455247497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12700800, while the sum is 55.

The spelling of 1331455247497 in words is "one trillion, three hundred thirty-one billion, four hundred fifty-five million, two hundred forty-seven thousand, four hundred ninety-seven".