Base | Representation |
---|---|
bin | 11110010001100110101010… |
… | …100101101001101110001011 |
3 | 122110110010101002202121200201 |
4 | 132101212222211221232023 |
5 | 114423022020120441420 |
6 | 1151104442443313031 |
7 | 40021565311360303 |
oct | 3621465245515613 |
9 | 573403332677621 |
10 | 133151143140235 |
11 | 394760a0072250 |
12 | 12b2570051b777 |
13 | 593b13943b17c |
14 | 24c479a5b4603 |
15 | 105d877e2510a |
hex | 7919aa969b8b |
133151143140235 has 32 divisors (see below), whose sum is σ = 176696696563200. Its totient is φ = 95509588320000.
The previous prime is 133151143140233. The next prime is 133151143140251. The reversal of 133151143140235 is 532041341151331.
It is not a de Polignac number, because 133151143140235 - 21 = 133151143140233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133151143140194 and 133151143140203.
It is not an unprimeable number, because it can be changed into a prime (133151143140233) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 599131666 + ... + 599353864.
It is an arithmetic number, because the mean of its divisors is an integer number (5521771767600).
Almost surely, 2133151143140235 is an apocalyptic number.
133151143140235 is a deficient number, since it is larger than the sum of its proper divisors (43545553422965).
133151143140235 is a wasteful number, since it uses less digits than its factorization.
133151143140235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 371539.
The product of its (nonzero) digits is 64800, while the sum is 37.
Adding to 133151143140235 its reverse (532041341151331), we get a palindrome (665192484291566).
The spelling of 133151143140235 in words is "one hundred thirty-three trillion, one hundred fifty-one billion, one hundred forty-three million, one hundred forty thousand, two hundred thirty-five".
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