Base | Representation |
---|---|
bin | 10011011000000110001… |
… | …000001010010000111101 |
3 | 11201021221111102211010100 |
4 | 103120012020022100331 |
5 | 133303444410224003 |
6 | 2455411404231313 |
7 | 165125603620554 |
oct | 23300610122075 |
9 | 4637844384110 |
10 | 1331542664253 |
11 | 47378213675a |
12 | 19608ab3b539 |
13 | 98743c6bc09 |
14 | 48638840d9b |
15 | 249831c4ba3 |
hex | 1360620a43d |
1331542664253 has 24 divisors (see below), whose sum is σ = 1968391705280. Its totient is φ = 866908526400.
The previous prime is 1331542664203. The next prime is 1331542664267. The reversal of 1331542664253 is 3524662451331.
1331542664253 is a `hidden beast` number, since 1 + 3 + 3 + 1 + 542 + 66 + 42 + 5 + 3 = 666.
It is a de Polignac number, because none of the positive numbers 2k-1331542664253 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1331542664199 and 1331542664208.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1331542664203) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2100753 + ... + 2660121.
Almost surely, 21331542664253 is an apocalyptic number.
It is an amenable number.
1331542664253 is a deficient number, since it is larger than the sum of its proper divisors (636849041027).
1331542664253 is a wasteful number, since it uses less digits than its factorization.
1331542664253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 565569 (or 565566 counting only the distinct ones).
The product of its digits is 1555200, while the sum is 45.
The spelling of 1331542664253 in words is "one trillion, three hundred thirty-one billion, five hundred forty-two million, six hundred sixty-four thousand, two hundred fifty-three".
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