Base | Representation |
---|---|
bin | 11110010001101010110100… |
… | …010100010001100111111111 |
3 | 122110110112212210121211212001 |
4 | 132101222310110101213333 |
5 | 114423110132414341133 |
6 | 1151110501101523131 |
7 | 40022113634331220 |
oct | 3621526424214777 |
9 | 573415783554761 |
10 | 133155601324543 |
11 | 39477a78652096 |
12 | 12b265455734a7 |
13 | 593b699c63855 |
14 | 24c4aa0717247 |
15 | 105da3950387d |
hex | 791ab45119ff |
133155601324543 has 64 divisors (see below), whose sum is σ = 168561082368000. Its totient is φ = 102614087931264.
The previous prime is 133155601324519. The next prime is 133155601324561. The reversal of 133155601324543 is 345423106551331.
It is a de Polignac number, because none of the positive numbers 2k-133155601324543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133155601324493 and 133155601324502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133155601324583) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 66968946 + ... + 68928592.
It is an arithmetic number, because the mean of its divisors is an integer number (2633766912000).
Almost surely, 2133155601324543 is an apocalyptic number.
133155601324543 is a deficient number, since it is larger than the sum of its proper divisors (35405481043457).
133155601324543 is a wasteful number, since it uses less digits than its factorization.
133155601324543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1960004.
The product of its (nonzero) digits is 1944000, while the sum is 46.
Adding to 133155601324543 its reverse (345423106551331), we get a palindrome (478578707875874).
The spelling of 133155601324543 in words is "one hundred thirty-three trillion, one hundred fifty-five billion, six hundred one million, three hundred twenty-four thousand, five hundred forty-three".
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