Base | Representation |
---|---|
bin | 111110000000100011… |
… | …0101000000111000001 |
3 | 110201201022201220210122 |
4 | 1330001012220013001 |
5 | 4140204100004140 |
6 | 141101330310025 |
7 | 12422614402364 |
oct | 1740106500701 |
9 | 421638656718 |
10 | 133162500545 |
11 | 5152383a648 |
12 | 21983a28315 |
13 | c732143a29 |
14 | 66334d20db |
15 | 36e5805ab5 |
hex | 1f011a81c1 |
133162500545 has 4 divisors (see below), whose sum is σ = 159795000660. Its totient is φ = 106530000432.
The previous prime is 133162500517. The next prime is 133162500589. The reversal of 133162500545 is 545005261331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 64390585009 + 68771915536 = 253753^2 + 262244^2 .
It is a cyclic number.
It is not a de Polignac number, because 133162500545 - 210 = 133162499521 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13316250050 + ... + 13316250059.
It is an arithmetic number, because the mean of its divisors is an integer number (39948750165).
Almost surely, 2133162500545 is an apocalyptic number.
It is an amenable number.
133162500545 is a deficient number, since it is larger than the sum of its proper divisors (26632500115).
133162500545 is an equidigital number, since it uses as much as digits as its factorization.
133162500545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26632500114.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 133162500545 its reverse (545005261331), we get a palindrome (678167761876).
The spelling of 133162500545 in words is "one hundred thirty-three billion, one hundred sixty-two million, five hundred thousand, five hundred forty-five".
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