1332000210121 has 4 divisors (see below), whose sum is σ = 1522285954432. Its totient is φ = 1141714465812.

The previous prime is 1332000210119. The next prime is 1332000210157. The reversal of 1332000210121 is 1210120002331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332000210121 - 2¹ = 1332000210119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1332000210095 and 1332000210104.

It is not an unprimeable number, because it can be changed into a prime (1332000250121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95142872145 + ... + 95142872158.

It is an arithmetic number, because the mean of its divisors is an integer number (380571488608).

Almost surely, 2^{1332000210121} is an apocalyptic number.

It is an amenable number.

1332000210121 is a deficient number, since it is larger than the sum of its proper divisors (190285744311).

1332000210121 is an equidigital number, since it uses as much as digits as its factorization.

1332000210121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190285744310.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1332000210121 its reverse (1210120002331), we get a palindrome (2542120212452).

The spelling of 1332000210121 in words is "one trillion, three hundred thirty-two billion, two hundred ten thousand, one hundred twenty-one".