Base | Representation |
---|---|
bin | 111110000001101011… |
… | …1010011100111100101 |
3 | 110201210222002210210102 |
4 | 1330003113103213211 |
5 | 4140243302134433 |
6 | 141105203233445 |
7 | 12423554644520 |
oct | 1740327234745 |
9 | 421728083712 |
10 | 133200427493 |
11 | 51543194731 |
12 | 21994678885 |
13 | c739c62b03 |
14 | 6638565bb7 |
15 | 36e8ce84e8 |
hex | 1f035d39e5 |
133200427493 has 4 divisors (see below), whose sum is σ = 152229060000. Its totient is φ = 114171794988.
The previous prime is 133200427487. The next prime is 133200427537. The reversal of 133200427493 is 394724002331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133200427493 - 224 = 133183650277 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133200424493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9514316243 + ... + 9514316256.
It is an arithmetic number, because the mean of its divisors is an integer number (38057265000).
Almost surely, 2133200427493 is an apocalyptic number.
It is an amenable number.
133200427493 is a deficient number, since it is larger than the sum of its proper divisors (19028632507).
133200427493 is an equidigital number, since it uses as much as digits as its factorization.
133200427493 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19028632506.
The product of its (nonzero) digits is 108864, while the sum is 38.
The spelling of 133200427493 in words is "one hundred thirty-three billion, two hundred million, four hundred twenty-seven thousand, four hundred ninety-three".
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