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133200441141 = 344400147047
BaseRepresentation
bin111110000001101011…
…1010110111100110101
3110201210222010111111220
41330003113112330311
54140243303104031
6141105203420553
712423555032355
oct1740327267465
9421728114456
10133200441141
11515431a3a09
1221994684759
13c739c690a1
14663856ab65
1536e8cec596
hex1f035d6f35

133200441141 has 4 divisors (see below), whose sum is σ = 177600588192. Its totient is φ = 88800294092.

The previous prime is 133200441119. The next prime is 133200441181. The reversal of 133200441141 is 141144002331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133200441141 - 25 = 133200441109 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133200441181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22200073521 + ... + 22200073526.

It is an arithmetic number, because the mean of its divisors is an integer number (44400147048).

Almost surely, 2133200441141 is an apocalyptic number.

It is an amenable number.

133200441141 is a deficient number, since it is larger than the sum of its proper divisors (44400147051).

133200441141 is an equidigital number, since it uses as much as digits as its factorization.

133200441141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44400147050.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 133200441141 its reverse (141144002331), we get a palindrome (274344443472).

The spelling of 133200441141 in words is "one hundred thirty-three billion, two hundred million, four hundred forty-one thousand, one hundred forty-one".

Divisors: 1 3 44400147047 133200441141