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1332011010181 is a prime number
BaseRepresentation
bin10011011000100010000…
…010110000100010000101
311201100011010201020221211
4103120202002300202011
5133310424304311211
62455530054411421
7165143321526565
oct23304202604205
94640133636854
101332011010181
114739a2542a05
1219619b960b71
13987b9cc0197
1448680b16da5
15249ae388e21
hex136220b0885

1332011010181 has 2 divisors, whose sum is σ = 1332011010182. Its totient is φ = 1332011010180.

The previous prime is 1332011010151. The next prime is 1332011010221. The reversal of 1332011010181 is 1810101102331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1148648062500 + 183362947681 = 1071750^2 + 428209^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1332011010181 is a prime.

It is a super-2 number, since 2×13320110101812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332011010151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666005505090 + 666005505091.

It is an arithmetic number, because the mean of its divisors is an integer number (666005505091).

Almost surely, 21332011010181 is an apocalyptic number.

It is an amenable number.

1332011010181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332011010181 is an equidigital number, since it uses as much as digits as its factorization.

1332011010181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 22.

The spelling of 1332011010181 in words is "one trillion, three hundred thirty-two billion, eleven million, ten thousand, one hundred eighty-one".