Base | Representation |
---|---|
bin | 11110010010010101001100… |
… | …110110011110110000100011 |
3 | 122110121220100101102020001012 |
4 | 132102111030312132300203 |
5 | 114424331333141213102 |
6 | 1151143424544531135 |
7 | 40025314452465653 |
oct | 3622251466366043 |
9 | 573556311366035 |
10 | 133201110101027 |
11 | 39495301119471 |
12 | 12b33326320aab |
13 | 5942a703b0767 |
14 | 24c6d7a784363 |
15 | 105ecee940752 |
hex | 79254cd9ec23 |
133201110101027 has 2 divisors, whose sum is σ = 133201110101028. Its totient is φ = 133201110101026.
The previous prime is 133201110100991. The next prime is 133201110101039. The reversal of 133201110101027 is 720101011102331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133201110101027 - 216 = 133201110035491 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133201110100993 and 133201110101011.
It is not a weakly prime, because it can be changed into another prime (133201110101827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66600555050513 + 66600555050514.
It is an arithmetic number, because the mean of its divisors is an integer number (66600555050514).
Almost surely, 2133201110101027 is an apocalyptic number.
133201110101027 is a deficient number, since it is larger than the sum of its proper divisors (1).
133201110101027 is an equidigital number, since it uses as much as digits as its factorization.
133201110101027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 133201110101027 its reverse (720101011102331), we get a palindrome (853302121203358).
The spelling of 133201110101027 in words is "one hundred thirty-three trillion, two hundred one billion, one hundred ten million, one hundred one thousand, twenty-seven".
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