Base | Representation |
---|---|
bin | 10011011000100010000… |
… | …011001011111000011111 |
3 | 11201100011010220221121221 |
4 | 103120202003023320133 |
5 | 133310424321402312 |
6 | 2455530101034211 |
7 | 165143322504313 |
oct | 23304203137037 |
9 | 4640133827557 |
10 | 1332011122207 |
11 | 4739a260a097 |
12 | 19619b9b5967 |
13 | 987ba02c17c |
14 | 48680b45b43 |
15 | 249ae3ac207 |
hex | 136220cbe1f |
1332011122207 has 2 divisors, whose sum is σ = 1332011122208. Its totient is φ = 1332011122206.
The previous prime is 1332011122187. The next prime is 1332011122271. The reversal of 1332011122207 is 7022211102331.
It is a weak prime.
It is an emirp because it is prime and its reverse (7022211102331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1332011122207 - 223 = 1332002733599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332011120207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666005561103 + 666005561104.
It is an arithmetic number, because the mean of its divisors is an integer number (666005561104).
Almost surely, 21332011122207 is an apocalyptic number.
1332011122207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332011122207 is an equidigital number, since it uses as much as digits as its factorization.
1332011122207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1332011122207 its reverse (7022211102331), we get a palindrome (8354222224538).
The spelling of 1332011122207 in words is "one trillion, three hundred thirty-two billion, eleven million, one hundred twenty-two thousand, two hundred seven".
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