Base | Representation |
---|---|
bin | 111110000001101111… |
… | …0011111111110011001 |
3 | 110201211002122121101012 |
4 | 1330003132133332121 |
5 | 4140244243004423 |
6 | 141105311503305 |
7 | 12423606660122 |
oct | 1740336377631 |
9 | 421732577335 |
10 | 133202313113 |
11 | 515442623a1 |
12 | 21995227b35 |
13 | c73a47316c |
14 | 66388d7049 |
15 | 36e906c078 |
hex | 1f0379ff99 |
133202313113 has 2 divisors, whose sum is σ = 133202313114. Its totient is φ = 133202313112.
The previous prime is 133202313071. The next prime is 133202313151. The reversal of 133202313113 is 311313202331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79316583424 + 53885729689 = 281632^2 + 232133^2 .
It is an emirp because it is prime and its reverse (311313202331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133202313113 is a prime.
It is not a weakly prime, because it can be changed into another prime (133202313163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601156556 + 66601156557.
It is an arithmetic number, because the mean of its divisors is an integer number (66601156557).
Almost surely, 2133202313113 is an apocalyptic number.
It is an amenable number.
133202313113 is a deficient number, since it is larger than the sum of its proper divisors (1).
133202313113 is an equidigital number, since it uses as much as digits as its factorization.
133202313113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 133202313113 its reverse (311313202331), we get a palindrome (444515515444).
The spelling of 133202313113 in words is "one hundred thirty-three billion, two hundred two million, three hundred thirteen thousand, one hundred thirteen".
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