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13320232311131 is a prime number
BaseRepresentation
bin1100000111010101101110…
…1101110001100101011011
31202011101211220002110020022
43001311123231301211123
53221214313432424011
644155121422221055
72543232526340624
oct301653355614533
952141756073208
1013320232311131
114276095977889
1215b1672a2478b
1375812834cb55
143409ba242a4b
1518175319e8db
hexc1d5bb7195b

13320232311131 has 2 divisors, whose sum is σ = 13320232311132. Its totient is φ = 13320232311130.

The previous prime is 13320232311103. The next prime is 13320232311149. The reversal of 13320232311131 is 13111323202331.

It is a strong prime.

It is an emirp because it is prime and its reverse (13111323202331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13320232311131 is a prime.

It is a super-2 number, since 2×133202323111312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13320232311131.

It is not a weakly prime, because it can be changed into another prime (13320232311181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660116155565 + 6660116155566.

It is an arithmetic number, because the mean of its divisors is an integer number (6660116155566).

Almost surely, 213320232311131 is an apocalyptic number.

13320232311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320232311131 is an equidigital number, since it uses as much as digits as its factorization.

13320232311131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 13320232311131 its reverse (13111323202331), we get a palindrome (26431555513462).

The spelling of 13320232311131 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-two million, three hundred eleven thousand, one hundred thirty-one".