Base | Representation |
---|---|
bin | 1100000111010101101110… |
… | …1101110001100101101101 |
3 | 1202011101211220002110020222 |
4 | 3001311123231301211231 |
5 | 3221214313432424044 |
6 | 44155121422221125 |
7 | 2543232526340651 |
oct | 301653355614555 |
9 | 52141756073228 |
10 | 13320232311149 |
11 | 42760959778a5 |
12 | 15b1672a247a5 |
13 | 75812834cb6a |
14 | 3409ba242a61 |
15 | 18175319e8ee |
hex | c1d5bb7196d |
13320232311149 has 2 divisors, whose sum is σ = 13320232311150. Its totient is φ = 13320232311148.
The previous prime is 13320232311131. The next prime is 13320232311157. The reversal of 13320232311149 is 94111323202331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10541593355524 + 2778638955625 = 3246782^2 + 1666925^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320232311149 - 220 = 13320231262573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13320232301149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660116155574 + 6660116155575.
It is an arithmetic number, because the mean of its divisors is an integer number (6660116155575).
Almost surely, 213320232311149 is an apocalyptic number.
It is an amenable number.
13320232311149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320232311149 is an equidigital number, since it uses as much as digits as its factorization.
13320232311149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 13320232311149 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-two million, three hundred eleven thousand, one hundred forty-nine".
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