Base | Representation |
---|---|
bin | 11110010010010110010101… |
… | …001101001000111010001111 |
3 | 122110122000110222120200221012 |
4 | 132102112111031020322033 |
5 | 114424341324421003044 |
6 | 1151144145230555435 |
7 | 40025356522454123 |
oct | 3622262515107217 |
9 | 573560428520835 |
10 | 133202324000399 |
11 | 39495874358a95 |
12 | 12b33604968b7b |
13 | 5942c04a30604 |
14 | 24c7053a91583 |
15 | 105ed712c459e |
hex | 792595348e8f |
133202324000399 has 2 divisors, whose sum is σ = 133202324000400. Its totient is φ = 133202324000398.
The previous prime is 133202324000359. The next prime is 133202324000411. The reversal of 133202324000399 is 993000423202331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133202324000399 - 212 = 133202323996303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133202324000309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601162000199 + 66601162000200.
It is an arithmetic number, because the mean of its divisors is an integer number (66601162000200).
Almost surely, 2133202324000399 is an apocalyptic number.
133202324000399 is a deficient number, since it is larger than the sum of its proper divisors (1).
133202324000399 is an equidigital number, since it uses as much as digits as its factorization.
133202324000399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 41.
The spelling of 133202324000399 in words is "one hundred thirty-three trillion, two hundred two billion, three hundred twenty-four million, three hundred ninety-nine", and thus it is an aban number.
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