13320232414031 has 4 divisors (see below), whose sum is σ = 13344583844952. Its totient is φ = 13295880983112.

The previous prime is 13320232413923. The next prime is 13320232414039. The reversal of 13320232414031 is 13041423202331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13320232414031 is a prime.

It is a super-2 number, since 2×13320232414031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13320232413985 and 13320232414003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13320232414039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12175714640 + ... + 12175715733.

It is an arithmetic number, because the mean of its divisors is an integer number (3336145961238).

Almost surely, 2^{13320232414031} is an apocalyptic number.

13320232414031 is a deficient number, since it is larger than the sum of its proper divisors (24351430921).

13320232414031 is an equidigital number, since it uses as much as digits as its factorization.

13320232414031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24351430920.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13320232414031 its reverse (13041423202331), we get a palindrome (26361655616362).

The spelling of 13320232414031 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-two million, four hundred fourteen thousand, thirty-one".