Base | Representation |
---|---|
bin | 11110010010010110101011… |
… | …101110001000111010011101 |
3 | 122110122001110022101100212002 |
4 | 132102112223232020322131 |
5 | 114424343113121444132 |
6 | 1151144250523252045 |
7 | 40025402060334512 |
oct | 3622265356107235 |
9 | 573561408340762 |
10 | 133202701749917 |
11 | 39495a48606878 |
12 | 12b336ab37a025 |
13 | 5942c65081337 |
14 | 24c708bd03309 |
15 | 105ed94540262 |
hex | 7925abb88e9d |
133202701749917 has 2 divisors, whose sum is σ = 133202701749918. Its totient is φ = 133202701749916.
The previous prime is 133202701749883. The next prime is 133202701749959. The reversal of 133202701749917 is 719947107202331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 133053710381881 + 148991368036 = 11534891^2 + 385994^2 .
It is a cyclic number.
It is not a de Polignac number, because 133202701749917 - 28 = 133202701749661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133202701749017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601350874958 + 66601350874959.
It is an arithmetic number, because the mean of its divisors is an integer number (66601350874959).
Almost surely, 2133202701749917 is an apocalyptic number.
It is an amenable number.
133202701749917 is a deficient number, since it is larger than the sum of its proper divisors (1).
133202701749917 is an equidigital number, since it uses as much as digits as its factorization.
133202701749917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4000752, while the sum is 56.
The spelling of 133202701749917 in words is "one hundred thirty-three trillion, two hundred two billion, seven hundred one million, seven hundred forty-nine thousand, nine hundred seventeen".
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