Base | Representation |
---|---|
bin | 1100000111010101111111… |
… | …1100101000000011010111 |
3 | 1202011102000211200201122021 |
4 | 3001311133330220003113 |
5 | 3221214440122004421 |
6 | 44155132440114011 |
7 | 2543234351006524 |
oct | 301653774500327 |
9 | 52142024621567 |
10 | 13320303313111 |
11 | 4276121a62703 |
12 | 15b1692765907 |
13 | 758139c7c762 |
14 | 3409c584614b |
15 | 181759527341 |
hex | c1d5ff280d7 |
13320303313111 has 4 divisors (see below), whose sum is σ = 13449626646352. Its totient is φ = 13190979979872.
The previous prime is 13320303313099. The next prime is 13320303313133. The reversal of 13320303313111 is 11131330302331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13320303313111 - 243 = 4524210290903 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13320303113111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64661666466 + ... + 64661666671.
It is an arithmetic number, because the mean of its divisors is an integer number (3362406661588).
Almost surely, 213320303313111 is an apocalyptic number.
13320303313111 is a deficient number, since it is larger than the sum of its proper divisors (129323333241).
13320303313111 is a wasteful number, since it uses less digits than its factorization.
13320303313111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129323333240.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 13320303313111 its reverse (11131330302331), we get a palindrome (24451633615442).
The spelling of 13320303313111 in words is "thirteen trillion, three hundred twenty billion, three hundred three million, three hundred thirteen thousand, one hundred eleven".
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