Base | Representation |
---|---|
bin | 1100000111010110000110… |
… | …1010111011110111011111 |
3 | 1202011102002212002212022021 |
4 | 3001311201222323313133 |
5 | 3221220020022330421 |
6 | 44155135352001011 |
7 | 2543235151544614 |
oct | 301654152736737 |
9 | 52142085085267 |
10 | 13320332230111 |
11 | 4276137313455 |
12 | 15b16a0390167 |
13 | 758142c657ca |
14 | 3409c961250b |
15 | 18175bd3a341 |
hex | c1d61abbddf |
13320332230111 has 4 divisors (see below), whose sum is σ = 13321549933000. Its totient is φ = 13319114527224.
The previous prime is 13320332230103. The next prime is 13320332230129. The reversal of 13320332230111 is 11103223302331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13320332230111 - 23 = 13320332230103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13320332233111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 608835036 + ... + 608856913.
It is an arithmetic number, because the mean of its divisors is an integer number (3330387483250).
Almost surely, 213320332230111 is an apocalyptic number.
13320332230111 is a deficient number, since it is larger than the sum of its proper divisors (1217702889).
13320332230111 is a wasteful number, since it uses less digits than its factorization.
13320332230111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1217702888.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13320332230111 its reverse (11103223302331), we get a palindrome (24423555532442).
The spelling of 13320332230111 in words is "thirteen trillion, three hundred twenty billion, three hundred thirty-two million, two hundred thirty thousand, one hundred eleven".
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