Base | Representation |
---|---|
bin | 10011011000100011010… |
… | …111111011001101011101 |
3 | 11201100012200201112102211 |
4 | 103120203113323031131 |
5 | 133311001013224112 |
6 | 2455532213120421 |
7 | 165144012354106 |
oct | 23304327731535 |
9 | 4640180645384 |
10 | 1332033336157 |
11 | 473a04101827 |
12 | 1961a7329111 |
13 | 987c1809214 |
14 | 48683a893ad |
15 | 249b12e90a7 |
hex | 136235fb35d |
1332033336157 has 4 divisors (see below), whose sum is σ = 1332699688000. Its totient is φ = 1331366984316.
The previous prime is 1332033336133. The next prime is 1332033336169. The reversal of 1332033336157 is 7516333302331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1332033336157 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1332033336107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333172923 + ... + 333176920.
It is an arithmetic number, because the mean of its divisors is an integer number (333174922000).
Almost surely, 21332033336157 is an apocalyptic number.
It is an amenable number.
1332033336157 is a deficient number, since it is larger than the sum of its proper divisors (666351843).
1332033336157 is an equidigital number, since it uses as much as digits as its factorization.
1332033336157 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 666351842.
The product of its (nonzero) digits is 306180, while the sum is 40.
Adding to 1332033336157 its reverse (7516333302331), we get a palindrome (8848366638488).
The spelling of 1332033336157 in words is "one trillion, three hundred thirty-two billion, thirty-three million, three hundred thirty-six thousand, one hundred fifty-seven".
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