Base | Representation |
---|---|
bin | 1100000111010110011111… |
… | …0000010101101110000001 |
3 | 1202011102100222012001121112 |
4 | 3001311213300111232001 |
5 | 3221220222140410032 |
6 | 44155153435533105 |
7 | 2543240531321642 |
oct | 301654760255601 |
9 | 52142328161545 |
10 | 13320434310017 |
11 | 42761899a560a |
12 | 15b170a5ba195 |
13 | 75815b156c13 |
14 | 3409d8dc56c9 |
15 | 181765ca11b2 |
hex | c1d67c15b81 |
13320434310017 has 2 divisors, whose sum is σ = 13320434310018. Its totient is φ = 13320434310016.
The previous prime is 13320434309993. The next prime is 13320434310031. The reversal of 13320434310017 is 71001343402331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11727994747456 + 1592439562561 = 3424616^2 + 1261919^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320434310017 - 218 = 13320434047873 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320434318017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660217155008 + 6660217155009.
It is an arithmetic number, because the mean of its divisors is an integer number (6660217155009).
Almost surely, 213320434310017 is an apocalyptic number.
It is an amenable number.
13320434310017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320434310017 is an equidigital number, since it uses as much as digits as its factorization.
13320434310017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 13320434310017 its reverse (71001343402331), we get a palindrome (84321777712348).
The spelling of 13320434310017 in words is "thirteen trillion, three hundred twenty billion, four hundred thirty-four million, three hundred ten thousand, seventeen".
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