Base | Representation |
---|---|
bin | 1100000111010110011111… |
… | …0000010101101110001111 |
3 | 1202011102100222012001122001 |
4 | 3001311213300111232033 |
5 | 3221220222140410111 |
6 | 44155153435533131 |
7 | 2543240531321662 |
oct | 301654760255617 |
9 | 52142328161561 |
10 | 13320434310031 |
11 | 42761899a5622 |
12 | 15b170a5ba1a7 |
13 | 75815b156c24 |
14 | 3409d8dc56d9 |
15 | 181765ca11c1 |
hex | c1d67c15b8f |
13320434310031 has 2 divisors, whose sum is σ = 13320434310032. Its totient is φ = 13320434310030.
The previous prime is 13320434310017. The next prime is 13320434310059. The reversal of 13320434310031 is 13001343402331.
It is an a-pointer prime, because the next prime (13320434310059) can be obtained adding 13320434310031 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13320434310031 - 235 = 13286074571663 is a prime.
It is a super-2 number, since 2×133204343100312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13320434610031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660217155015 + 6660217155016.
It is an arithmetic number, because the mean of its divisors is an integer number (6660217155016).
Almost surely, 213320434310031 is an apocalyptic number.
13320434310031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320434310031 is an equidigital number, since it uses as much as digits as its factorization.
13320434310031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 13320434310031 its reverse (13001343402331), we get a palindrome (26321777712362).
The spelling of 13320434310031 in words is "thirteen trillion, three hundred twenty billion, four hundred thirty-four million, three hundred ten thousand, thirty-one".
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