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13320440121334 = 26660220060667
BaseRepresentation
bin1100000111010110100000…
…0110100000011111110110
31202011102101101010022020111
43001311220012200133312
53221220230132340314
644155154204253234
72543240631604363
oct301655006403766
952142341108214
1013320440121334
114276192204755
1215b171054121a
1375815c410078
143409d9a9946a
1518176654cec4
hexc1d681a07f6

13320440121334 has 4 divisors (see below), whose sum is σ = 19980660182004. Its totient is φ = 6660220060666.

The previous prime is 13320440121299. The next prime is 13320440121349. The reversal of 13320440121334 is 43312104402331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13320440121296 and 13320440121305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3330110030332 + ... + 3330110030335.

It is an arithmetic number, because the mean of its divisors is an integer number (4995165045501).

Almost surely, 213320440121334 is an apocalyptic number.

13320440121334 is a deficient number, since it is larger than the sum of its proper divisors (6660220060670).

13320440121334 is an equidigital number, since it uses as much as digits as its factorization.

13320440121334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6660220060669.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13320440121334 its reverse (43312104402331), we get a palindrome (56632544523665).

The spelling of 13320440121334 in words is "thirteen trillion, three hundred twenty billion, four hundred forty million, one hundred twenty-one thousand, three hundred thirty-four".

Divisors: 1 2 6660220060667 13320440121334