133204410133 has 4 divisors (see below), whose sum is σ = 133205346540. Its totient is φ = 133203473728.

The previous prime is 133204410127. The next prime is 133204410137. The reversal of 133204410133 is 331014402331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 67861292004 + 65343118129 = 260502^2 + 255623^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133204410133 is a prime.

It is a super-3 number, since 3×133204410133³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133204410098 and 133204410107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133204410137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205810 + ... + 555667.

It is an arithmetic number, because the mean of its divisors is an integer number (33301336635).

Almost surely, 2^133204410133 is an apocalyptic number.

It is an amenable number.

133204410133 is a deficient number, since it is larger than the sum of its proper divisors (936407).

133204410133 is an equidigital number, since it uses as much as digits as its factorization.

133204410133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 936406.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 133204410133 its reverse (331014402331), we get a palindrome (464218812464).

The spelling of 133204410133 in words is "one hundred thirty-three billion, two hundred four million, four hundred ten thousand, one hundred thirty-three".