Base | Representation |
---|---|
bin | 11000110011111010… |
… | …11101010101011111 |
3 | 1021101022202121221022 |
4 | 30121331131111133 |
5 | 204240013140411 |
6 | 10041435154355 |
7 | 651043620314 |
oct | 143175352537 |
9 | 37338677838 |
10 | 13320443231 |
11 | 5716052177 |
12 | 26b8ba59bb |
13 | 13438a9894 |
14 | 905140d0b |
15 | 52e64cedb |
hex | 319f5d55f |
13320443231 has 2 divisors, whose sum is σ = 13320443232. Its totient is φ = 13320443230.
The previous prime is 13320443203. The next prime is 13320443237. The reversal of 13320443231 is 13234402331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13320443231 - 210 = 13320442207 is a prime.
It is a super-2 number, since 2×133204432312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13320443231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13320443237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660221615 + 6660221616.
It is an arithmetic number, because the mean of its divisors is an integer number (6660221616).
Almost surely, 213320443231 is an apocalyptic number.
13320443231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320443231 is an equidigital number, since it uses as much as digits as its factorization.
13320443231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13320443231 its reverse (13234402331), we get a palindrome (26554845562).
The spelling of 13320443231 in words is "thirteen billion, three hundred twenty million, four hundred forty-three thousand, two hundred thirty-one".
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