133210101113 has 4 divisors (see below), whose sum is σ = 133211330448. Its totient is φ = 133208871780.

The previous prime is 133210101109. The next prime is 133210101139. The reversal of 133210101113 is 311101012331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311101012331 = 857 ⋅363011683.

It is a cyclic number.

It is not a de Polignac number, because 133210101113 - 2² = 133210101109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133210101091 and 133210101100.

It is not an unprimeable number, because it can be changed into a prime (133210101173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434531 + ... + 674712.

It is an arithmetic number, because the mean of its divisors is an integer number (33302832612).

Almost surely, 2^133210101113 is an apocalyptic number.

It is an amenable number.

133210101113 is a deficient number, since it is larger than the sum of its proper divisors (1229335).

133210101113 is a wasteful number, since it uses less digits than its factorization.

133210101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1229334.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 133210101113 its reverse (311101012331), we get a palindrome (444311113444).

The spelling of 133210101113 in words is "one hundred thirty-three billion, two hundred ten million, one hundred one thousand, one hundred thirteen".