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1332102113 is a prime number
BaseRepresentation
bin100111101100110…
…0100001111100001
310102211120210120022
41033121210033201
510212004231423
6340103323225
745003452426
oct11731441741
93384523508
101332102113
11623a34041
12312150515
13182c97a04
14c8cb9d4d
157be31dc8
hex4f6643e1

1332102113 has 2 divisors, whose sum is σ = 1332102114. Its totient is φ = 1332102112.

The previous prime is 1332102077. The next prime is 1332102119. The reversal of 1332102113 is 3112012331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1279278289 + 52823824 = 35767^2 + 7268^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332102113 - 228 = 1063666657 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1332102091 and 1332102100.

It is not a weakly prime, because it can be changed into another prime (1332102119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666051056 + 666051057.

It is an arithmetic number, because the mean of its divisors is an integer number (666051057).

Almost surely, 21332102113 is an apocalyptic number.

It is an amenable number.

1332102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332102113 is an equidigital number, since it uses as much as digits as its factorization.

1332102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1332102113 is about 36497.9740944617. The cubic root of 1332102113 is about 1100.3035286348.

Adding to 1332102113 its reverse (3112012331), we get a palindrome (4444114444).

The spelling of 1332102113 in words is "one billion, three hundred thirty-two million, one hundred two thousand, one hundred thirteen".