Base | Representation |
---|---|
bin | 1100000111011000111110… |
… | …0011111010011001111011 |
3 | 1202011111002111211101120021 |
4 | 3001312033203322121323 |
5 | 3221223104122003201 |
6 | 44155344013511311 |
7 | 2543263220642125 |
oct | 301661743723173 |
9 | 52144074741507 |
10 | 13321102141051 |
11 | 42764a1972991 |
12 | 15b18761a2537 |
13 | 758236612003 |
14 | 340a5d988215 |
15 | 1817a471bea1 |
hex | c1d8f8fa67b |
13321102141051 has 2 divisors, whose sum is σ = 13321102141052. Its totient is φ = 13321102141050.
The previous prime is 13321102141049. The next prime is 13321102141181. The reversal of 13321102141051 is 15014120112331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13321102141051 - 21 = 13321102141049 is a prime.
Together with 13321102141049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13321102141751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660551070525 + 6660551070526.
It is an arithmetic number, because the mean of its divisors is an integer number (6660551070526).
Almost surely, 213321102141051 is an apocalyptic number.
13321102141051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321102141051 is an equidigital number, since it uses as much as digits as its factorization.
13321102141051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13321102141051 its reverse (15014120112331), we get a palindrome (28335222253382).
The spelling of 13321102141051 in words is "thirteen trillion, three hundred twenty-one billion, one hundred two million, one hundred forty-one thousand, fifty-one".
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