13321113000000 has 784 divisors, whose sum is σ = 48105396743040. Its totient is φ = 3233433600000.

The previous prime is 13321112999981. The next prime is 13321113000017. The reversal of 13321113000000 is 31112331.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 2846997661 + ... + 2847002339.

Almost surely, 2^{13321113000000} is an apocalyptic number.

13321113000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13321113000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24052698371520).

13321113000000 is an abundant number, since it is smaller than the sum of its proper divisors (34784283743040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13321113000000 is an frugal number, since it uses more digits than its factorization.

13321113000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4810 (or 4775 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13321113000000 its reverse (31112331), we get a palindrome (13321144112331).

The spelling of 13321113000000 in words is "thirteen trillion, three hundred twenty-one billion, one hundred thirteen million", and thus it is an aban number.