Base | Representation |
---|---|
bin | 10011011000101000000… |
… | …111110011111101110111 |
3 | 11201100102020121210022012 |
4 | 103120220013303331313 |
5 | 133311131411421023 |
6 | 2455544140354435 |
7 | 165146000442125 |
oct | 23305007637567 |
9 | 4640366553265 |
10 | 1332112998263 |
11 | 473a45072083 |
12 | 196209b45a1b |
13 | 9880517b868 |
14 | 486904a4915 |
15 | 249b82d2978 |
hex | 136281f3f77 |
1332112998263 has 2 divisors, whose sum is σ = 1332112998264. Its totient is φ = 1332112998262.
The previous prime is 1332112998211. The next prime is 1332112998277. The reversal of 1332112998263 is 3628992112331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1332112998263 - 212 = 1332112994167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332112998563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666056499131 + 666056499132.
It is an arithmetic number, because the mean of its divisors is an integer number (666056499132).
Almost surely, 21332112998263 is an apocalyptic number.
1332112998263 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332112998263 is an equidigital number, since it uses as much as digits as its factorization.
1332112998263 is an evil number, because the sum of its binary digits is even.
The product of its digits is 839808, while the sum is 50.
The spelling of 1332112998263 in words is "one trillion, three hundred thirty-two billion, one hundred twelve million, nine hundred ninety-eight thousand, two hundred sixty-three".
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