Base | Representation |
---|---|
bin | 10011011000101000001… |
… | …000100101001110101001 |
3 | 11201100102021000001002110 |
4 | 103120220020211032221 |
5 | 133311131434400131 |
6 | 2455544144552533 |
7 | 165146002242321 |
oct | 23305010451651 |
9 | 4640367001073 |
10 | 1332113200041 |
11 | 473a4519a738 |
12 | 19620a022749 |
13 | 9880521c660 |
14 | 48690518281 |
15 | 249b8322646 |
hex | 136282253a9 |
1332113200041 has 32 divisors (see below), whose sum is σ = 1936517732352. Its totient is φ = 809594856000.
The previous prime is 1332113200031. The next prime is 1332113200043. The reversal of 1332113200041 is 1400023112331.
It is not a de Polignac number, because 1332113200041 - 27 = 1332113199913 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1332113199990 and 1332113200017.
It is not an unprimeable number, because it can be changed into a prime (1332113200043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9130416 + ... + 9275166.
It is an arithmetic number, because the mean of its divisors is an integer number (60516179136).
Almost surely, 21332113200041 is an apocalyptic number.
It is an amenable number.
1332113200041 is a deficient number, since it is larger than the sum of its proper divisors (604404532311).
1332113200041 is a wasteful number, since it uses less digits than its factorization.
1332113200041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147693.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1332113200041 its reverse (1400023112331), we get a palindrome (2732136312372).
The spelling of 1332113200041 in words is "one trillion, three hundred thirty-two billion, one hundred thirteen million, two hundred thousand, forty-one".
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