1332121314301 has 4 divisors (see below), whose sum is σ = 1332183045312. Its totient is φ = 1332059583292.

The previous prime is 1332121314259. The next prime is 1332121314317. The reversal of 1332121314301 is 1034131212331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1332121314301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332121314001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30833125 + ... + 30876298.

It is an arithmetic number, because the mean of its divisors is an integer number (333045761328).

Almost surely, 2^{1332121314301} is an apocalyptic number.

It is an amenable number.

1332121314301 is a deficient number, since it is larger than the sum of its proper divisors (61731011).

1332121314301 is an equidigital number, since it uses as much as digits as its factorization.

1332121314301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61731010.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1332121314301 its reverse (1034131212331), we get a palindrome (2366252526632).

The spelling of 1332121314301 in words is "one trillion, three hundred thirty-two billion, one hundred twenty-one million, three hundred fourteen thousand, three hundred one".