Base | Representation |
---|---|
bin | 11110010010011111011101… |
… | …110100000111010111100111 |
3 | 122110122221210112021101110011 |
4 | 132102133131310013113213 |
5 | 114430021421310034342 |
6 | 1151152450400511051 |
7 | 40026154550154205 |
oct | 3622373564072747 |
9 | 573587715241404 |
10 | 133212132111847 |
11 | 39499a47820318 |
12 | 12b354a161b487 |
13 | 5943b08a43859 |
14 | 24c7704544075 |
15 | 10602473cb717 |
hex | 7927ddd075e7 |
133212132111847 has 2 divisors, whose sum is σ = 133212132111848. Its totient is φ = 133212132111846.
The previous prime is 133212132111823. The next prime is 133212132111859. The reversal of 133212132111847 is 748111231212331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133212132111847 - 215 = 133212132079079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133212132121847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66606066055923 + 66606066055924.
It is an arithmetic number, because the mean of its divisors is an integer number (66606066055924).
Almost surely, 2133212132111847 is an apocalyptic number.
133212132111847 is a deficient number, since it is larger than the sum of its proper divisors (1).
133212132111847 is an equidigital number, since it uses as much as digits as its factorization.
133212132111847 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48384, while the sum is 40.
The spelling of 133212132111847 in words is "one hundred thirty-three trillion, two hundred twelve billion, one hundred thirty-two million, one hundred eleven thousand, eight hundred forty-seven".
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