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13321213323941 is a prime number
BaseRepresentation
bin1100000111011001011000…
…1100000010101010100101
31202011111101021001001211002
43001312112030002222211
53221223321102331231
644155403024523045
72543266040661365
oct301662614025245
952144337031732
1013321213323941
114276549702276
1215b18a7480485
1375825366c8c3
14340a7064a9a5
151817ae3800cb
hexc1d96302aa5

13321213323941 has 2 divisors, whose sum is σ = 13321213323942. Its totient is φ = 13321213323940.

The previous prime is 13321213323923. The next prime is 13321213323949. The reversal of 13321213323941 is 14932331212331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12237228330625 + 1083984993316 = 3498175^2 + 1041146^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321213323941 - 26 = 13321213323877 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13321213323895 and 13321213323904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13321213323949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660606661970 + 6660606661971.

It is an arithmetic number, because the mean of its divisors is an integer number (6660606661971).

Almost surely, 213321213323941 is an apocalyptic number.

It is an amenable number.

13321213323941 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321213323941 is an equidigital number, since it uses as much as digits as its factorization.

13321213323941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69984, while the sum is 38.

The spelling of 13321213323941 in words is "thirteen trillion, three hundred twenty-one billion, two hundred thirteen million, three hundred twenty-three thousand, nine hundred forty-one".