133212212113333 has 4 divisors (see below), whose sum is σ = 133292123460000. Its totient is φ = 133132300766668.

The previous prime is 133212212113289. The next prime is 133212212113447. The reversal of 133212212113333 is 333311212212331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133212212113333 - 2⁴¹ = 131013188857781 is a prime.

It is a super-2 number, since 2×133212212113333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133212212113295 and 133212212113304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133212212113633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39955670833 + ... + 39955674166.

It is an arithmetic number, because the mean of its divisors is an integer number (33323030865000).

Almost surely, 2^{133212212113333} is an apocalyptic number.

It is an amenable number.

133212212113333 is a deficient number, since it is larger than the sum of its proper divisors (79911346667).

133212212113333 is an equidigital number, since it uses as much as digits as its factorization.

133212212113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79911346666.

The product of its digits is 11664, while the sum is 31.

Adding to 133212212113333 its reverse (333311212212331), we get a palindrome (466523424325664).

The spelling of 133212212113333 in words is "one hundred thirty-three trillion, two hundred twelve billion, two hundred twelve million, one hundred thirteen thousand, three hundred thirty-three".