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133212433 = 904314731
BaseRepresentation
bin1111111000010…
…10100100010001
3100021122220002211
413330022210101
5233100244213
621115112121
73205200304
oct774124421
9307586084
10133212433
1169216522
1238742641
13217a1a33
1413998b3b
15ba6553d
hex7f0a911

133212433 has 4 divisors (see below), whose sum is σ = 133236208. Its totient is φ = 133188660.

The previous prime is 133212419. The next prime is 133212449. The reversal of 133212433 is 334212331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133212433 - 29 = 133211921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133212473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1678 + ... + 16408.

It is an arithmetic number, because the mean of its divisors is an integer number (33309052).

Almost surely, 2133212433 is an apocalyptic number.

It is an amenable number.

133212433 is a deficient number, since it is larger than the sum of its proper divisors (23775).

133212433 is an equidigital number, since it uses as much as digits as its factorization.

133212433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23774.

The product of its digits is 1296, while the sum is 22.

The square root of 133212433 is about 11541.7690585109. The cubic root of 133212433 is about 510.7184964581.

Adding to 133212433 its reverse (334212331), we get a palindrome (467424764).

The spelling of 133212433 in words is "one hundred thirty-three million, two hundred twelve thousand, four hundred thirty-three".

Divisors: 1 9043 14731 133212433