Base | Representation |
---|---|
bin | 10011011000101001010… |
… | …000011010011000011101 |
3 | 11201100110120102200220122 |
4 | 103120221100122120131 |
5 | 133311201244424411 |
6 | 2455550100324325 |
7 | 165146321266154 |
oct | 23305120323035 |
9 | 4640416380818 |
10 | 1332132029981 |
11 | 473a54890975 |
12 | 1962143a36a5 |
13 | 988090b332c |
14 | 48692c1a59b |
15 | 249b9ce19db |
hex | 1362941a61d |
1332132029981 has 2 divisors, whose sum is σ = 1332132029982. Its totient is φ = 1332132029980.
The previous prime is 1332132029971. The next prime is 1332132030011. The reversal of 1332132029981 is 1899202312331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1283790972025 + 48341057956 = 1133045^2 + 219866^2 .
It is an emirp because it is prime and its reverse (1899202312331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1332132029981 - 210 = 1332132028957 is a prime.
It is a super-2 number, since 2×13321320299812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332132029911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666066014990 + 666066014991.
It is an arithmetic number, because the mean of its divisors is an integer number (666066014991).
Almost surely, 21332132029981 is an apocalyptic number.
It is an amenable number.
1332132029981 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332132029981 is an equidigital number, since it uses as much as digits as its factorization.
1332132029981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 44.
The spelling of 1332132029981 in words is "one trillion, three hundred thirty-two billion, one hundred thirty-two million, twenty-nine thousand, nine hundred eighty-one".
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