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1332133000201 = 7350191812379
BaseRepresentation
bin10011011000101001010…
…100000111010000001001
311201100110122020222210201
4103120221110013100021
5133311202022001301
62455550133212201
7165146332446613
oct23305124072011
94640418228721
101332133000201
11473a55393903
12196214791061
1398809362b23
1448692dcddb3
15249b9e34201
hex13629507409

1332133000201 has 4 divisors (see below), whose sum is σ = 1332135547600. Its totient is φ = 1332130452804.

The previous prime is 1332133000171. The next prime is 1332133000229. The reversal of 1332133000201 is 1020003312331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332133000201 - 29 = 1332132999689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1332133000241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171171 + ... + 1641208.

It is an arithmetic number, because the mean of its divisors is an integer number (333033886900).

Almost surely, 21332133000201 is an apocalyptic number.

It is an amenable number.

1332133000201 is a deficient number, since it is larger than the sum of its proper divisors (2547399).

1332133000201 is an equidigital number, since it uses as much as digits as its factorization.

1332133000201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2547398.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 1332133000201 its reverse (1020003312331), we get a palindrome (2352136312532).

The spelling of 1332133000201 in words is "one trillion, three hundred thirty-two billion, one hundred thirty-three million, two hundred one", and thus it is an aban number.

Divisors: 1 735019 1812379 1332133000201