Base | Representation |
---|---|
bin | 1100000111011001110100… |
… | …1101010100101001010001 |
3 | 1202011111200110122201112021 |
4 | 3001312131031110221101 |
5 | 3221224041230201431 |
6 | 44155422433131441 |
7 | 2543302001031463 |
oct | 301663515245121 |
9 | 52144613581467 |
10 | 13321331100241 |
11 | 42765aa13535a |
12 | 15b191a9b9b81 |
13 | 758271b98618 |
14 | 340a82148133 |
15 | 1817b9896b11 |
hex | c1d9d354a51 |
13321331100241 has 2 divisors, whose sum is σ = 13321331100242. Its totient is φ = 13321331100240.
The previous prime is 13321331100151. The next prime is 13321331100313. The reversal of 13321331100241 is 14200113312331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9479495896641 + 3841835203600 = 3078879^2 + 1960060^2 .
It is a cyclic number.
It is not a de Polignac number, because 13321331100241 - 29 = 13321331099729 is a prime.
It is not a weakly prime, because it can be changed into another prime (13321331800241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660665550120 + 6660665550121.
It is an arithmetic number, because the mean of its divisors is an integer number (6660665550121).
Almost surely, 213321331100241 is an apocalyptic number.
It is an amenable number.
13321331100241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321331100241 is an equidigital number, since it uses as much as digits as its factorization.
13321331100241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13321331100241 its reverse (14200113312331), we get a palindrome (27521444412572).
The spelling of 13321331100241 in words is "thirteen trillion, three hundred twenty-one billion, three hundred thirty-one million, one hundred thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •