Base | Representation |
---|---|
bin | 1100000111011001110100… |
… | …1101010100100111110111 |
3 | 1202011111200110122201101221 |
4 | 3001312131031110213313 |
5 | 3221224041230201101 |
6 | 44155422433131211 |
7 | 2543302001031304 |
oct | 301663515244767 |
9 | 52144613581357 |
10 | 13321331100151 |
11 | 42765aa135288 |
12 | 15b191a9b9b07 |
13 | 758271b98579 |
14 | 340a821480ab |
15 | 1817b9896aa1 |
hex | c1d9d3549f7 |
13321331100151 has 2 divisors, whose sum is σ = 13321331100152. Its totient is φ = 13321331100150.
The previous prime is 13321331100137. The next prime is 13321331100241. The reversal of 13321331100151 is 15100113312331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13321331100151 - 27 = 13321331100023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321331100131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660665550075 + 6660665550076.
It is an arithmetic number, because the mean of its divisors is an integer number (6660665550076).
Almost surely, 213321331100151 is an apocalyptic number.
13321331100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321331100151 is an equidigital number, since it uses as much as digits as its factorization.
13321331100151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 25.
Adding to 13321331100151 its reverse (15100113312331), we get a palindrome (28421444412482).
The spelling of 13321331100151 in words is "thirteen trillion, three hundred twenty-one billion, three hundred thirty-one million, one hundred thousand, one hundred fifty-one".
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