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1332133113301 = 9541913960879
BaseRepresentation
bin10011011000101001010…
…100100010110111010101
311201100110122110201221121
4103120221110202313111
5133311202034111201
62455550135443541
7165146333430424
oct23305124426725
94640418421847
101332133113301
11473a55460881
121962148265b1
13988093a2453
144869301d2bb
15249b9e579a1
hex13629522dd5

1332133113301 has 4 divisors (see below), whose sum is σ = 1332147169600. Its totient is φ = 1332119057004.

The previous prime is 1332133113229. The next prime is 1332133113317. The reversal of 1332133113301 is 1033113312331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332133113301 - 29 = 1332133112789 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332133113331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6885021 + ... + 7075858.

It is an arithmetic number, because the mean of its divisors is an integer number (333036792400).

Almost surely, 21332133113301 is an apocalyptic number.

It is an amenable number.

1332133113301 is a deficient number, since it is larger than the sum of its proper divisors (14056299).

1332133113301 is an equidigital number, since it uses as much as digits as its factorization.

1332133113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14056298.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1332133113301 its reverse (1033113312331), we get a palindrome (2365246425632).

The spelling of 1332133113301 in words is "one trillion, three hundred thirty-two billion, one hundred thirty-three million, one hundred thirteen thousand, three hundred one".

Divisors: 1 95419 13960879 1332133113301