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1332134303143 = 7190304900449
BaseRepresentation
bin10011011000101001011…
…001000101010110100111
311201100110201201012002211
4103120221121011112213
5133311202340200033
62455550221144251
7165146346514360
oct23305131052647
94640421635084
101332134303143
11473a560a3816
121962150bb087
13988096cabb7
144869324cb67
15249ba0e02cd
hex136296455a7

1332134303143 has 4 divisors (see below), whose sum is σ = 1522439203600. Its totient is φ = 1141829402688.

The previous prime is 1332134303063. The next prime is 1332134303161. The reversal of 1332134303143 is 3413034312331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1332134303143 - 213 = 1332134294951 is a prime.

It is a super-2 number, since 2×13321343031432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1332134303543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95152450218 + ... + 95152450231.

It is an arithmetic number, because the mean of its divisors is an integer number (380609800900).

Almost surely, 21332134303143 is an apocalyptic number.

1332134303143 is a deficient number, since it is larger than the sum of its proper divisors (190304900457).

1332134303143 is an equidigital number, since it uses as much as digits as its factorization.

1332134303143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190304900456.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 1332134303143 its reverse (3413034312331), we get a palindrome (4745168615474).

The spelling of 1332134303143 in words is "one trillion, three hundred thirty-two billion, one hundred thirty-four million, three hundred three thousand, one hundred forty-three".

Divisors: 1 7 190304900449 1332134303143