Base | Representation |
---|---|
bin | 1100000111011010000101… |
… | …1101010111010011011111 |
3 | 1202011111212102211212000211 |
4 | 3001312201131113103133 |
5 | 3221224213004224203 |
6 | 44155433501433251 |
7 | 2543303525140264 |
oct | 301664135272337 |
9 | 52144772755024 |
10 | 13321402414303 |
11 | 42766364136a5 |
12 | 15b193a86b827 |
13 | 7582838a72a9 |
14 | 340a8b7cd26b |
15 | 1817c0c81c6d |
hex | c1da17574df |
13321402414303 has 2 divisors, whose sum is σ = 13321402414304. Its totient is φ = 13321402414302.
The previous prime is 13321402414279. The next prime is 13321402414379. The reversal of 13321402414303 is 30341420412331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13321402414303 - 233 = 13312812479711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321402414003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660701207151 + 6660701207152.
It is an arithmetic number, because the mean of its divisors is an integer number (6660701207152).
Almost surely, 213321402414303 is an apocalyptic number.
13321402414303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321402414303 is an equidigital number, since it uses as much as digits as its factorization.
13321402414303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13321402414303 its reverse (30341420412331), we get a palindrome (43662822826634).
The spelling of 13321402414303 in words is "thirteen trillion, three hundred twenty-one billion, four hundred two million, four hundred fourteen thousand, three hundred three".
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