Search a number
-
+
133214401141 = 716912715281
BaseRepresentation
bin111110000010000110…
…0100111001001110101
3110201211221101202000221
41330010030213021311
54140310341314031
6141110422534341
712424114504153
oct1740414471165
9421757352027
10133214401141
11515500692a8
12219992973b1
13c73cb16243
14663a3623d3
1536ea158a11
hex1f04327275

133214401141 has 8 divisors (see below), whose sum is σ = 135286210368. Its totient is φ = 131148024000.

The previous prime is 133214401129. The next prime is 133214401181. The reversal of 133214401141 is 141104412331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133214401141 - 215 = 133214368373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133214401181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1308580 + ... + 1406701.

It is an arithmetic number, because the mean of its divisors is an integer number (16910776296).

Almost surely, 2133214401141 is an apocalyptic number.

It is an amenable number.

133214401141 is a deficient number, since it is larger than the sum of its proper divisors (2071809227).

133214401141 is an equidigital number, since it uses as much as digits as its factorization.

133214401141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2716043.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 133214401141 its reverse (141104412331), we get a palindrome (274318813472).

The spelling of 133214401141 in words is "one hundred thirty-three billion, two hundred fourteen million, four hundred one thousand, one hundred forty-one".

Divisors: 1 71 691 49061 2715281 192784951 1876259171 133214401141