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13321552351973 is a prime number
BaseRepresentation
bin1100000111011010101001…
…1001010101001011100101
31202011112020212222110211212
43001312222121111023211
53221230014400230343
644155500415241205
72543310325450325
oct301665231251345
952145225873755
1013321552351973
114276703013028
1215b1980b19205
137582a89839c8
14340aa369d285
151817cdeecc18
hexc1daa6552e5

13321552351973 has 2 divisors, whose sum is σ = 13321552351974. Its totient is φ = 13321552351972.

The previous prime is 13321552351963. The next prime is 13321552352093. The reversal of 13321552351973 is 37915325512331.

13321552351973 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12388583746564 + 932968605409 = 3519742^2 + 965903^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321552351973 - 212 = 13321552347877 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13321552351903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660776175986 + 6660776175987.

It is an arithmetic number, because the mean of its divisors is an integer number (6660776175987).

Almost surely, 213321552351973 is an apocalyptic number.

It is an amenable number.

13321552351973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321552351973 is an equidigital number, since it uses as much as digits as its factorization.

13321552351973 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2551500, while the sum is 50.

The spelling of 13321552351973 in words is "thirteen trillion, three hundred twenty-one billion, five hundred fifty-two million, three hundred fifty-one thousand, nine hundred seventy-three".