Base | Representation |
---|---|
bin | 11110010010100110111000… |
… | …111111110000110000000011 |
3 | 122110200201101010102200000021 |
4 | 132102212320333300300003 |
5 | 114430134233202430111 |
6 | 1151200245425234311 |
7 | 40026556243046233 |
oct | 3622467077606003 |
9 | 573621333380007 |
10 | 133220104342531 |
11 | 394a2368951218 |
12 | 12b36b47492997 |
13 | 59447a95b310b |
14 | 24c7c5d25dcc3 |
15 | 106056223dd71 |
hex | 7929b8ff0c03 |
133220104342531 has 2 divisors, whose sum is σ = 133220104342532. Its totient is φ = 133220104342530.
The previous prime is 133220104342529. The next prime is 133220104342541. The reversal of 133220104342531 is 135243401022331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133220104342531 - 21 = 133220104342529 is a prime.
It is a super-2 number, since 2×1332201043425312 (a number of 29 digits) contains 22 as substring.
Together with 133220104342529, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (133220104342541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610052171265 + 66610052171266.
It is an arithmetic number, because the mean of its divisors is an integer number (66610052171266).
Almost surely, 2133220104342531 is an apocalyptic number.
133220104342531 is a deficient number, since it is larger than the sum of its proper divisors (1).
133220104342531 is an equidigital number, since it uses as much as digits as its factorization.
133220104342531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 133220104342531 its reverse (135243401022331), we get a palindrome (268463505364862).
The spelling of 133220104342531 in words is "one hundred thirty-three trillion, two hundred twenty billion, one hundred four million, three hundred forty-two thousand, five hundred thirty-one".
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