Base | Representation |
---|---|
bin | 11000110100000110… |
… | …11100101000100001 |
3 | 1021101102201101112221 |
4 | 30122003130220201 |
5 | 204240413410332 |
6 | 10041532551041 |
7 | 651063146452 |
oct | 143203345041 |
9 | 37342641487 |
10 | 13322013217 |
11 | 5716a24787 |
12 | 26b9622481 |
13 | 1344009376 |
14 | 90542d129 |
15 | 52e85d297 |
hex | 31a0dca21 |
13322013217 has 2 divisors, whose sum is σ = 13322013218. Its totient is φ = 13322013216.
The previous prime is 13322013197. The next prime is 13322013251. The reversal of 13322013217 is 71231022331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13280488081 + 41525136 = 115241^2 + 6444^2 .
It is a cyclic number.
It is not a de Polignac number, because 13322013217 - 211 = 13322011169 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13322013191 and 13322013200.
It is not a weakly prime, because it can be changed into another prime (13322010217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661006608 + 6661006609.
It is an arithmetic number, because the mean of its divisors is an integer number (6661006609).
Almost surely, 213322013217 is an apocalyptic number.
It is an amenable number.
13322013217 is a deficient number, since it is larger than the sum of its proper divisors (1).
13322013217 is an equidigital number, since it uses as much as digits as its factorization.
13322013217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 13322013217 its reverse (71231022331), we get a palindrome (84553035548).
The spelling of 13322013217 in words is "thirteen billion, three hundred twenty-two million, thirteen thousand, two hundred seventeen".
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