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13322020304023 is a prime number
BaseRepresentation
bin1100000111011100011001…
…0010011011010010010111
31202011120110111111220101021
43001313012102123102113
53221231444144212043
644200015053142011
72543325040126114
oct301670622332227
952146414456337
1013322020304023
114276923180362
1215b1a9178a907
137583518c7902
14340b098b190b
1518180a1353ed
hexc1dc649b497

13322020304023 has 2 divisors, whose sum is σ = 13322020304024. Its totient is φ = 13322020304022.

The previous prime is 13322020303979. The next prime is 13322020304039. The reversal of 13322020304023 is 32040302022331.

13322020304023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13322020304023 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13322020304053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661010152011 + 6661010152012.

It is an arithmetic number, because the mean of its divisors is an integer number (6661010152012).

Almost surely, 213322020304023 is an apocalyptic number.

13322020304023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13322020304023 is an equidigital number, since it uses as much as digits as its factorization.

13322020304023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 13322020304023 its reverse (32040302022331), we get a palindrome (45362322326354).

The spelling of 13322020304023 in words is "thirteen trillion, three hundred twenty-two billion, twenty million, three hundred four thousand, twenty-three".